3.6.40 \(\int \frac {(a+b x^3)^{5/2} (A+B x^3)}{(e x)^{3/2}} \, dx\) [540]

3.6.40.1 Optimal result
3.6.40.2 Mathematica [C] (verified)
3.6.40.3 Rubi [A] (verified)
3.6.40.4 Maple [C] (verified)
3.6.40.5 Fricas [F]
3.6.40.6 Sympy [C] (verification not implemented)
3.6.40.7 Maxima [F]
3.6.40.8 Giac [F]
3.6.40.9 Mupad [F(-1)]

3.6.40.1 Optimal result

Integrand size = 26, antiderivative size = 650 \[ \int \frac {\left (a+b x^3\right )^{5/2} \left (A+B x^3\right )}{(e x)^{3/2}} \, dx=\frac {27 a (20 A b+a B) (e x)^{5/2} \sqrt {a+b x^3}}{224 e^4}+\frac {81 \left (1+\sqrt {3}\right ) a^2 (20 A b+a B) \sqrt {e x} \sqrt {a+b x^3}}{448 b^{2/3} e^2 \left (\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x\right )}+\frac {3 (20 A b+a B) (e x)^{5/2} \left (a+b x^3\right )^{3/2}}{28 e^4}+\frac {(20 A b+a B) (e x)^{5/2} \left (a+b x^3\right )^{5/2}}{10 a e^4}-\frac {2 A \left (a+b x^3\right )^{7/2}}{a e \sqrt {e x}}-\frac {81 \sqrt [4]{3} a^{7/3} (20 A b+a B) \sqrt {e x} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt {\frac {a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x\right )^2}} E\left (\arccos \left (\frac {\sqrt [3]{a}+\left (1-\sqrt {3}\right ) \sqrt [3]{b} x}{\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x}\right )|\frac {1}{4} \left (2+\sqrt {3}\right )\right )}{448 b^{2/3} e^2 \sqrt {\frac {\sqrt [3]{b} x \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x\right )^2}} \sqrt {a+b x^3}}-\frac {27\ 3^{3/4} \left (1-\sqrt {3}\right ) a^{7/3} (20 A b+a B) \sqrt {e x} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt {\frac {a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x\right )^2}} \operatorname {EllipticF}\left (\arccos \left (\frac {\sqrt [3]{a}+\left (1-\sqrt {3}\right ) \sqrt [3]{b} x}{\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x}\right ),\frac {1}{4} \left (2+\sqrt {3}\right )\right )}{896 b^{2/3} e^2 \sqrt {\frac {\sqrt [3]{b} x \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x\right )^2}} \sqrt {a+b x^3}} \]

output
3/28*(20*A*b+B*a)*(e*x)^(5/2)*(b*x^3+a)^(3/2)/e^4+1/10*(20*A*b+B*a)*(e*x)^ 
(5/2)*(b*x^3+a)^(5/2)/a/e^4-2*A*(b*x^3+a)^(7/2)/a/e/(e*x)^(1/2)+27/224*a*( 
20*A*b+B*a)*(e*x)^(5/2)*(b*x^3+a)^(1/2)/e^4+81/448*a^2*(20*A*b+B*a)*(1+3^( 
1/2))*(e*x)^(1/2)*(b*x^3+a)^(1/2)/b^(2/3)/e^2/(a^(1/3)+b^(1/3)*x*(1+3^(1/2 
)))-81/448*3^(1/4)*a^(7/3)*(20*A*b+B*a)*(a^(1/3)+b^(1/3)*x)*((a^(1/3)+b^(1 
/3)*x*(1-3^(1/2)))^2/(a^(1/3)+b^(1/3)*x*(1+3^(1/2)))^2)^(1/2)/(a^(1/3)+b^( 
1/3)*x*(1-3^(1/2)))*(a^(1/3)+b^(1/3)*x*(1+3^(1/2)))*EllipticE((1-(a^(1/3)+ 
b^(1/3)*x*(1-3^(1/2)))^2/(a^(1/3)+b^(1/3)*x*(1+3^(1/2)))^2)^(1/2),1/4*6^(1 
/2)+1/4*2^(1/2))*(e*x)^(1/2)*((a^(2/3)-a^(1/3)*b^(1/3)*x+b^(2/3)*x^2)/(a^( 
1/3)+b^(1/3)*x*(1+3^(1/2)))^2)^(1/2)/b^(2/3)/e^2/(b*x^3+a)^(1/2)/(b^(1/3)* 
x*(a^(1/3)+b^(1/3)*x)/(a^(1/3)+b^(1/3)*x*(1+3^(1/2)))^2)^(1/2)-27/896*3^(3 
/4)*a^(7/3)*(20*A*b+B*a)*(a^(1/3)+b^(1/3)*x)*((a^(1/3)+b^(1/3)*x*(1-3^(1/2 
)))^2/(a^(1/3)+b^(1/3)*x*(1+3^(1/2)))^2)^(1/2)/(a^(1/3)+b^(1/3)*x*(1-3^(1/ 
2)))*(a^(1/3)+b^(1/3)*x*(1+3^(1/2)))*EllipticF((1-(a^(1/3)+b^(1/3)*x*(1-3^ 
(1/2)))^2/(a^(1/3)+b^(1/3)*x*(1+3^(1/2)))^2)^(1/2),1/4*6^(1/2)+1/4*2^(1/2) 
)*(1-3^(1/2))*(e*x)^(1/2)*((a^(2/3)-a^(1/3)*b^(1/3)*x+b^(2/3)*x^2)/(a^(1/3 
)+b^(1/3)*x*(1+3^(1/2)))^2)^(1/2)/b^(2/3)/e^2/(b*x^3+a)^(1/2)/(b^(1/3)*x*( 
a^(1/3)+b^(1/3)*x)/(a^(1/3)+b^(1/3)*x*(1+3^(1/2)))^2)^(1/2)
 
3.6.40.2 Mathematica [C] (verified)

Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.

Time = 10.06 (sec) , antiderivative size = 87, normalized size of antiderivative = 0.13 \[ \int \frac {\left (a+b x^3\right )^{5/2} \left (A+B x^3\right )}{(e x)^{3/2}} \, dx=\frac {2 x \sqrt {a+b x^3} \left (-5 A \left (a+b x^3\right )^3+\frac {a^2 (20 A b+a B) x^3 \operatorname {Hypergeometric2F1}\left (-\frac {5}{2},\frac {5}{6},\frac {11}{6},-\frac {b x^3}{a}\right )}{\sqrt {1+\frac {b x^3}{a}}}\right )}{5 a (e x)^{3/2}} \]

input
Integrate[((a + b*x^3)^(5/2)*(A + B*x^3))/(e*x)^(3/2),x]
 
output
(2*x*Sqrt[a + b*x^3]*(-5*A*(a + b*x^3)^3 + (a^2*(20*A*b + a*B)*x^3*Hyperge 
ometric2F1[-5/2, 5/6, 11/6, -((b*x^3)/a)])/Sqrt[1 + (b*x^3)/a]))/(5*a*(e*x 
)^(3/2))
 
3.6.40.3 Rubi [A] (verified)

Time = 0.74 (sec) , antiderivative size = 684, normalized size of antiderivative = 1.05, number of steps used = 10, number of rules used = 9, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.346, Rules used = {955, 811, 811, 811, 851, 837, 25, 766, 2420}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {\left (a+b x^3\right )^{5/2} \left (A+B x^3\right )}{(e x)^{3/2}} \, dx\)

\(\Big \downarrow \) 955

\(\displaystyle \frac {(a B+20 A b) \int (e x)^{3/2} \left (b x^3+a\right )^{5/2}dx}{a e^3}-\frac {2 A \left (a+b x^3\right )^{7/2}}{a e \sqrt {e x}}\)

\(\Big \downarrow \) 811

\(\displaystyle \frac {(a B+20 A b) \left (\frac {3}{4} a \int (e x)^{3/2} \left (b x^3+a\right )^{3/2}dx+\frac {(e x)^{5/2} \left (a+b x^3\right )^{5/2}}{10 e}\right )}{a e^3}-\frac {2 A \left (a+b x^3\right )^{7/2}}{a e \sqrt {e x}}\)

\(\Big \downarrow \) 811

\(\displaystyle \frac {(a B+20 A b) \left (\frac {3}{4} a \left (\frac {9}{14} a \int (e x)^{3/2} \sqrt {b x^3+a}dx+\frac {(e x)^{5/2} \left (a+b x^3\right )^{3/2}}{7 e}\right )+\frac {(e x)^{5/2} \left (a+b x^3\right )^{5/2}}{10 e}\right )}{a e^3}-\frac {2 A \left (a+b x^3\right )^{7/2}}{a e \sqrt {e x}}\)

\(\Big \downarrow \) 811

\(\displaystyle \frac {(a B+20 A b) \left (\frac {3}{4} a \left (\frac {9}{14} a \left (\frac {3}{8} a \int \frac {(e x)^{3/2}}{\sqrt {b x^3+a}}dx+\frac {(e x)^{5/2} \sqrt {a+b x^3}}{4 e}\right )+\frac {(e x)^{5/2} \left (a+b x^3\right )^{3/2}}{7 e}\right )+\frac {(e x)^{5/2} \left (a+b x^3\right )^{5/2}}{10 e}\right )}{a e^3}-\frac {2 A \left (a+b x^3\right )^{7/2}}{a e \sqrt {e x}}\)

\(\Big \downarrow \) 851

\(\displaystyle \frac {(a B+20 A b) \left (\frac {3}{4} a \left (\frac {9}{14} a \left (\frac {3 a \int \frac {e^2 x^2}{\sqrt {b x^3+a}}d\sqrt {e x}}{4 e}+\frac {(e x)^{5/2} \sqrt {a+b x^3}}{4 e}\right )+\frac {(e x)^{5/2} \left (a+b x^3\right )^{3/2}}{7 e}\right )+\frac {(e x)^{5/2} \left (a+b x^3\right )^{5/2}}{10 e}\right )}{a e^3}-\frac {2 A \left (a+b x^3\right )^{7/2}}{a e \sqrt {e x}}\)

\(\Big \downarrow \) 837

\(\displaystyle \frac {(a B+20 A b) \left (\frac {3}{4} a \left (\frac {9}{14} a \left (\frac {3 a \left (-\frac {\left (1-\sqrt {3}\right ) a^{2/3} e^2 \int \frac {1}{\sqrt {b x^3+a}}d\sqrt {e x}}{2 b^{2/3}}-\frac {\int -\frac {2 b^{2/3} x^2 e^2+\left (1-\sqrt {3}\right ) a^{2/3} e^2}{\sqrt {b x^3+a}}d\sqrt {e x}}{2 b^{2/3}}\right )}{4 e}+\frac {(e x)^{5/2} \sqrt {a+b x^3}}{4 e}\right )+\frac {(e x)^{5/2} \left (a+b x^3\right )^{3/2}}{7 e}\right )+\frac {(e x)^{5/2} \left (a+b x^3\right )^{5/2}}{10 e}\right )}{a e^3}-\frac {2 A \left (a+b x^3\right )^{7/2}}{a e \sqrt {e x}}\)

\(\Big \downarrow \) 25

\(\displaystyle \frac {(a B+20 A b) \left (\frac {3}{4} a \left (\frac {9}{14} a \left (\frac {3 a \left (\frac {\int \frac {2 b^{2/3} x^2 e^2+\left (1-\sqrt {3}\right ) a^{2/3} e^2}{\sqrt {b x^3+a}}d\sqrt {e x}}{2 b^{2/3}}-\frac {\left (1-\sqrt {3}\right ) a^{2/3} e^2 \int \frac {1}{\sqrt {b x^3+a}}d\sqrt {e x}}{2 b^{2/3}}\right )}{4 e}+\frac {(e x)^{5/2} \sqrt {a+b x^3}}{4 e}\right )+\frac {(e x)^{5/2} \left (a+b x^3\right )^{3/2}}{7 e}\right )+\frac {(e x)^{5/2} \left (a+b x^3\right )^{5/2}}{10 e}\right )}{a e^3}-\frac {2 A \left (a+b x^3\right )^{7/2}}{a e \sqrt {e x}}\)

\(\Big \downarrow \) 766

\(\displaystyle \frac {(a B+20 A b) \left (\frac {3}{4} a \left (\frac {9}{14} a \left (\frac {3 a \left (\frac {\int \frac {2 b^{2/3} x^2 e^2+\left (1-\sqrt {3}\right ) a^{2/3} e^2}{\sqrt {b x^3+a}}d\sqrt {e x}}{2 b^{2/3}}-\frac {\left (1-\sqrt {3}\right ) \sqrt [3]{a} e \sqrt {e x} \left (\sqrt [3]{a} e+\sqrt [3]{b} e x\right ) \sqrt {\frac {a^{2/3} e^2-\sqrt [3]{a} \sqrt [3]{b} e^2 x+b^{2/3} e^2 x^2}{\left (\sqrt [3]{a} e+\left (1+\sqrt {3}\right ) \sqrt [3]{b} e x\right )^2}} \operatorname {EllipticF}\left (\arccos \left (\frac {\left (1-\sqrt {3}\right ) \sqrt [3]{b} x e+\sqrt [3]{a} e}{\left (1+\sqrt {3}\right ) \sqrt [3]{b} x e+\sqrt [3]{a} e}\right ),\frac {1}{4} \left (2+\sqrt {3}\right )\right )}{4 \sqrt [4]{3} b^{2/3} \sqrt {a+b x^3} \sqrt {\frac {\sqrt [3]{b} e x \left (\sqrt [3]{a} e+\sqrt [3]{b} e x\right )}{\left (\sqrt [3]{a} e+\left (1+\sqrt {3}\right ) \sqrt [3]{b} e x\right )^2}}}\right )}{4 e}+\frac {(e x)^{5/2} \sqrt {a+b x^3}}{4 e}\right )+\frac {(e x)^{5/2} \left (a+b x^3\right )^{3/2}}{7 e}\right )+\frac {(e x)^{5/2} \left (a+b x^3\right )^{5/2}}{10 e}\right )}{a e^3}-\frac {2 A \left (a+b x^3\right )^{7/2}}{a e \sqrt {e x}}\)

\(\Big \downarrow \) 2420

\(\displaystyle \frac {(a B+20 A b) \left (\frac {3}{4} a \left (\frac {9}{14} a \left (\frac {3 a \left (\frac {\frac {\left (1+\sqrt {3}\right ) e^3 \sqrt {e x} \sqrt {a+b x^3}}{\sqrt [3]{a} e+\left (1+\sqrt {3}\right ) \sqrt [3]{b} e x}-\frac {\sqrt [4]{3} \sqrt [3]{a} e \sqrt {e x} \left (\sqrt [3]{a} e+\sqrt [3]{b} e x\right ) \sqrt {\frac {a^{2/3} e^2-\sqrt [3]{a} \sqrt [3]{b} e^2 x+b^{2/3} e^2 x^2}{\left (\sqrt [3]{a} e+\left (1+\sqrt {3}\right ) \sqrt [3]{b} e x\right )^2}} E\left (\arccos \left (\frac {\left (1-\sqrt {3}\right ) \sqrt [3]{b} x e+\sqrt [3]{a} e}{\left (1+\sqrt {3}\right ) \sqrt [3]{b} x e+\sqrt [3]{a} e}\right )|\frac {1}{4} \left (2+\sqrt {3}\right )\right )}{\sqrt {a+b x^3} \sqrt {\frac {\sqrt [3]{b} e x \left (\sqrt [3]{a} e+\sqrt [3]{b} e x\right )}{\left (\sqrt [3]{a} e+\left (1+\sqrt {3}\right ) \sqrt [3]{b} e x\right )^2}}}}{2 b^{2/3}}-\frac {\left (1-\sqrt {3}\right ) \sqrt [3]{a} e \sqrt {e x} \left (\sqrt [3]{a} e+\sqrt [3]{b} e x\right ) \sqrt {\frac {a^{2/3} e^2-\sqrt [3]{a} \sqrt [3]{b} e^2 x+b^{2/3} e^2 x^2}{\left (\sqrt [3]{a} e+\left (1+\sqrt {3}\right ) \sqrt [3]{b} e x\right )^2}} \operatorname {EllipticF}\left (\arccos \left (\frac {\left (1-\sqrt {3}\right ) \sqrt [3]{b} x e+\sqrt [3]{a} e}{\left (1+\sqrt {3}\right ) \sqrt [3]{b} x e+\sqrt [3]{a} e}\right ),\frac {1}{4} \left (2+\sqrt {3}\right )\right )}{4 \sqrt [4]{3} b^{2/3} \sqrt {a+b x^3} \sqrt {\frac {\sqrt [3]{b} e x \left (\sqrt [3]{a} e+\sqrt [3]{b} e x\right )}{\left (\sqrt [3]{a} e+\left (1+\sqrt {3}\right ) \sqrt [3]{b} e x\right )^2}}}\right )}{4 e}+\frac {(e x)^{5/2} \sqrt {a+b x^3}}{4 e}\right )+\frac {(e x)^{5/2} \left (a+b x^3\right )^{3/2}}{7 e}\right )+\frac {(e x)^{5/2} \left (a+b x^3\right )^{5/2}}{10 e}\right )}{a e^3}-\frac {2 A \left (a+b x^3\right )^{7/2}}{a e \sqrt {e x}}\)

input
Int[((a + b*x^3)^(5/2)*(A + B*x^3))/(e*x)^(3/2),x]
 
output
(-2*A*(a + b*x^3)^(7/2))/(a*e*Sqrt[e*x]) + ((20*A*b + a*B)*(((e*x)^(5/2)*( 
a + b*x^3)^(5/2))/(10*e) + (3*a*(((e*x)^(5/2)*(a + b*x^3)^(3/2))/(7*e) + ( 
9*a*(((e*x)^(5/2)*Sqrt[a + b*x^3])/(4*e) + (3*a*((((1 + Sqrt[3])*e^3*Sqrt[ 
e*x]*Sqrt[a + b*x^3])/(a^(1/3)*e + (1 + Sqrt[3])*b^(1/3)*e*x) - (3^(1/4)*a 
^(1/3)*e*Sqrt[e*x]*(a^(1/3)*e + b^(1/3)*e*x)*Sqrt[(a^(2/3)*e^2 - a^(1/3)*b 
^(1/3)*e^2*x + b^(2/3)*e^2*x^2)/(a^(1/3)*e + (1 + Sqrt[3])*b^(1/3)*e*x)^2] 
*EllipticE[ArcCos[(a^(1/3)*e + (1 - Sqrt[3])*b^(1/3)*e*x)/(a^(1/3)*e + (1 
+ Sqrt[3])*b^(1/3)*e*x)], (2 + Sqrt[3])/4])/(Sqrt[(b^(1/3)*e*x*(a^(1/3)*e 
+ b^(1/3)*e*x))/(a^(1/3)*e + (1 + Sqrt[3])*b^(1/3)*e*x)^2]*Sqrt[a + b*x^3] 
))/(2*b^(2/3)) - ((1 - Sqrt[3])*a^(1/3)*e*Sqrt[e*x]*(a^(1/3)*e + b^(1/3)*e 
*x)*Sqrt[(a^(2/3)*e^2 - a^(1/3)*b^(1/3)*e^2*x + b^(2/3)*e^2*x^2)/(a^(1/3)* 
e + (1 + Sqrt[3])*b^(1/3)*e*x)^2]*EllipticF[ArcCos[(a^(1/3)*e + (1 - Sqrt[ 
3])*b^(1/3)*e*x)/(a^(1/3)*e + (1 + Sqrt[3])*b^(1/3)*e*x)], (2 + Sqrt[3])/4 
])/(4*3^(1/4)*b^(2/3)*Sqrt[(b^(1/3)*e*x*(a^(1/3)*e + b^(1/3)*e*x))/(a^(1/3 
)*e + (1 + Sqrt[3])*b^(1/3)*e*x)^2]*Sqrt[a + b*x^3])))/(4*e)))/14))/4))/(a 
*e^3)
 

3.6.40.3.1 Defintions of rubi rules used

rule 25
Int[-(Fx_), x_Symbol] :> Simp[Identity[-1]   Int[Fx, x], x]
 

rule 766
Int[1/Sqrt[(a_) + (b_.)*(x_)^6], x_Symbol] :> With[{r = Numer[Rt[b/a, 3]], 
s = Denom[Rt[b/a, 3]]}, Simp[x*(s + r*x^2)*(Sqrt[(s^2 - r*s*x^2 + r^2*x^4)/ 
(s + (1 + Sqrt[3])*r*x^2)^2]/(2*3^(1/4)*s*Sqrt[a + b*x^6]*Sqrt[r*x^2*((s + 
r*x^2)/(s + (1 + Sqrt[3])*r*x^2)^2)]))*EllipticF[ArcCos[(s + (1 - Sqrt[3])* 
r*x^2)/(s + (1 + Sqrt[3])*r*x^2)], (2 + Sqrt[3])/4], x]] /; FreeQ[{a, b}, x 
]
 

rule 811
Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(c* 
x)^(m + 1)*((a + b*x^n)^p/(c*(m + n*p + 1))), x] + Simp[a*n*(p/(m + n*p + 1 
))   Int[(c*x)^m*(a + b*x^n)^(p - 1), x], x] /; FreeQ[{a, b, c, m}, x] && I 
GtQ[n, 0] && GtQ[p, 0] && NeQ[m + n*p + 1, 0] && IntBinomialQ[a, b, c, n, m 
, p, x]
 

rule 837
Int[(x_)^4/Sqrt[(a_) + (b_.)*(x_)^6], x_Symbol] :> With[{r = Numer[Rt[b/a, 
3]], s = Denom[Rt[b/a, 3]]}, Simp[(Sqrt[3] - 1)*(s^2/(2*r^2))   Int[1/Sqrt[ 
a + b*x^6], x], x] - Simp[1/(2*r^2)   Int[((Sqrt[3] - 1)*s^2 - 2*r^2*x^4)/S 
qrt[a + b*x^6], x], x]] /; FreeQ[{a, b}, x]
 

rule 851
Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> With[{k = 
 Denominator[m]}, Simp[k/c   Subst[Int[x^(k*(m + 1) - 1)*(a + b*(x^(k*n)/c^ 
n))^p, x], x, (c*x)^(1/k)], x]] /; FreeQ[{a, b, c, p}, x] && IGtQ[n, 0] && 
FractionQ[m] && IntBinomialQ[a, b, c, n, m, p, x]
 

rule 955
Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_.)*((c_) + (d_.)*(x_)^(n 
_)), x_Symbol] :> Simp[c*(e*x)^(m + 1)*((a + b*x^n)^(p + 1)/(a*e*(m + 1))), 
 x] + Simp[(a*d*(m + 1) - b*c*(m + n*(p + 1) + 1))/(a*e^n*(m + 1))   Int[(e 
*x)^(m + n)*(a + b*x^n)^p, x], x] /; FreeQ[{a, b, c, d, e, p}, x] && NeQ[b* 
c - a*d, 0] && (IntegerQ[n] || GtQ[e, 0]) && ((GtQ[n, 0] && LtQ[m, -1]) || 
(LtQ[n, 0] && GtQ[m + n, -1])) &&  !ILtQ[p, -1]
 

rule 2420
Int[((c_) + (d_.)*(x_)^4)/Sqrt[(a_) + (b_.)*(x_)^6], x_Symbol] :> With[{r = 
 Numer[Rt[b/a, 3]], s = Denom[Rt[b/a, 3]]}, Simp[(1 + Sqrt[3])*d*s^3*x*(Sqr 
t[a + b*x^6]/(2*a*r^2*(s + (1 + Sqrt[3])*r*x^2))), x] - Simp[3^(1/4)*d*s*x* 
(s + r*x^2)*(Sqrt[(s^2 - r*s*x^2 + r^2*x^4)/(s + (1 + Sqrt[3])*r*x^2)^2]/(2 
*r^2*Sqrt[(r*x^2*(s + r*x^2))/(s + (1 + Sqrt[3])*r*x^2)^2]*Sqrt[a + b*x^6]) 
)*EllipticE[ArcCos[(s + (1 - Sqrt[3])*r*x^2)/(s + (1 + Sqrt[3])*r*x^2)], (2 
 + Sqrt[3])/4], x]] /; FreeQ[{a, b, c, d}, x] && EqQ[2*Rt[b/a, 3]^2*c - (1 
- Sqrt[3])*d, 0]
 
3.6.40.4 Maple [C] (verified)

Result contains complex when optimal does not.

Time = 4.94 (sec) , antiderivative size = 1166, normalized size of antiderivative = 1.79

method result size
risch \(\text {Expression too large to display}\) \(1166\)
elliptic \(\text {Expression too large to display}\) \(1341\)
default \(\text {Expression too large to display}\) \(6530\)

input
int((b*x^3+a)^(5/2)*(B*x^3+A)/(e*x)^(3/2),x,method=_RETURNVERBOSE)
 
output
-1/1120*(b*x^3+a)^(1/2)*(-112*B*b^2*x^9-160*A*b^2*x^6-344*B*a*b*x^6-620*A* 
a*b*x^3-367*B*a^2*x^3+2240*A*a^2)/e/(e*x)^(1/2)+81/448*a^2*(20*A*b+B*a)*(x 
*(x+1/2/b*(-a*b^2)^(1/3)+1/2*I*3^(1/2)/b*(-a*b^2)^(1/3))*(x+1/2/b*(-a*b^2) 
^(1/3)-1/2*I*3^(1/2)/b*(-a*b^2)^(1/3))+(1/2/b*(-a*b^2)^(1/3)-1/2*I*3^(1/2) 
/b*(-a*b^2)^(1/3))*((-3/2/b*(-a*b^2)^(1/3)+1/2*I*3^(1/2)/b*(-a*b^2)^(1/3)) 
*x/(-1/2/b*(-a*b^2)^(1/3)+1/2*I*3^(1/2)/b*(-a*b^2)^(1/3))/(x-1/b*(-a*b^2)^ 
(1/3)))^(1/2)*(x-1/b*(-a*b^2)^(1/3))^2*(1/b*(-a*b^2)^(1/3)*(x+1/2/b*(-a*b^ 
2)^(1/3)+1/2*I*3^(1/2)/b*(-a*b^2)^(1/3))/(-1/2/b*(-a*b^2)^(1/3)-1/2*I*3^(1 
/2)/b*(-a*b^2)^(1/3))/(x-1/b*(-a*b^2)^(1/3)))^(1/2)*(1/b*(-a*b^2)^(1/3)*(x 
+1/2/b*(-a*b^2)^(1/3)-1/2*I*3^(1/2)/b*(-a*b^2)^(1/3))/(-1/2/b*(-a*b^2)^(1/ 
3)+1/2*I*3^(1/2)/b*(-a*b^2)^(1/3))/(x-1/b*(-a*b^2)^(1/3)))^(1/2)*(((-1/2/b 
*(-a*b^2)^(1/3)+1/2*I*3^(1/2)/b*(-a*b^2)^(1/3))/b*(-a*b^2)^(1/3)+1/b^2*(-a 
*b^2)^(2/3))/(-3/2/b*(-a*b^2)^(1/3)+1/2*I*3^(1/2)/b*(-a*b^2)^(1/3))*b/(-a* 
b^2)^(1/3)*EllipticF(((-3/2/b*(-a*b^2)^(1/3)+1/2*I*3^(1/2)/b*(-a*b^2)^(1/3 
))*x/(-1/2/b*(-a*b^2)^(1/3)+1/2*I*3^(1/2)/b*(-a*b^2)^(1/3))/(x-1/b*(-a*b^2 
)^(1/3)))^(1/2),((3/2/b*(-a*b^2)^(1/3)+1/2*I*3^(1/2)/b*(-a*b^2)^(1/3))*(1/ 
2/b*(-a*b^2)^(1/3)-1/2*I*3^(1/2)/b*(-a*b^2)^(1/3))/(1/2/b*(-a*b^2)^(1/3)+1 
/2*I*3^(1/2)/b*(-a*b^2)^(1/3))/(3/2/b*(-a*b^2)^(1/3)-1/2*I*3^(1/2)/b*(-a*b 
^2)^(1/3)))^(1/2))+(1/2/b*(-a*b^2)^(1/3)+1/2*I*3^(1/2)/b*(-a*b^2)^(1/3))*E 
llipticE(((-3/2/b*(-a*b^2)^(1/3)+1/2*I*3^(1/2)/b*(-a*b^2)^(1/3))*x/(-1/...
 
3.6.40.5 Fricas [F]

\[ \int \frac {\left (a+b x^3\right )^{5/2} \left (A+B x^3\right )}{(e x)^{3/2}} \, dx=\int { \frac {{\left (B x^{3} + A\right )} {\left (b x^{3} + a\right )}^{\frac {5}{2}}}{\left (e x\right )^{\frac {3}{2}}} \,d x } \]

input
integrate((b*x^3+a)^(5/2)*(B*x^3+A)/(e*x)^(3/2),x, algorithm="fricas")
 
output
integral((B*b^2*x^9 + (2*B*a*b + A*b^2)*x^6 + (B*a^2 + 2*A*a*b)*x^3 + A*a^ 
2)*sqrt(b*x^3 + a)*sqrt(e*x)/(e^2*x^2), x)
 
3.6.40.6 Sympy [C] (verification not implemented)

Result contains complex when optimal does not.

Time = 21.62 (sec) , antiderivative size = 311, normalized size of antiderivative = 0.48 \[ \int \frac {\left (a+b x^3\right )^{5/2} \left (A+B x^3\right )}{(e x)^{3/2}} \, dx=\frac {A a^{\frac {5}{2}} \Gamma \left (- \frac {1}{6}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, - \frac {1}{6} \\ \frac {5}{6} \end {matrix}\middle | {\frac {b x^{3} e^{i \pi }}{a}} \right )}}{3 e^{\frac {3}{2}} \sqrt {x} \Gamma \left (\frac {5}{6}\right )} + \frac {2 A a^{\frac {3}{2}} b x^{\frac {5}{2}} \Gamma \left (\frac {5}{6}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, \frac {5}{6} \\ \frac {11}{6} \end {matrix}\middle | {\frac {b x^{3} e^{i \pi }}{a}} \right )}}{3 e^{\frac {3}{2}} \Gamma \left (\frac {11}{6}\right )} + \frac {A \sqrt {a} b^{2} x^{\frac {11}{2}} \Gamma \left (\frac {11}{6}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, \frac {11}{6} \\ \frac {17}{6} \end {matrix}\middle | {\frac {b x^{3} e^{i \pi }}{a}} \right )}}{3 e^{\frac {3}{2}} \Gamma \left (\frac {17}{6}\right )} + \frac {B a^{\frac {5}{2}} x^{\frac {5}{2}} \Gamma \left (\frac {5}{6}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, \frac {5}{6} \\ \frac {11}{6} \end {matrix}\middle | {\frac {b x^{3} e^{i \pi }}{a}} \right )}}{3 e^{\frac {3}{2}} \Gamma \left (\frac {11}{6}\right )} + \frac {2 B a^{\frac {3}{2}} b x^{\frac {11}{2}} \Gamma \left (\frac {11}{6}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, \frac {11}{6} \\ \frac {17}{6} \end {matrix}\middle | {\frac {b x^{3} e^{i \pi }}{a}} \right )}}{3 e^{\frac {3}{2}} \Gamma \left (\frac {17}{6}\right )} + \frac {B \sqrt {a} b^{2} x^{\frac {17}{2}} \Gamma \left (\frac {17}{6}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, \frac {17}{6} \\ \frac {23}{6} \end {matrix}\middle | {\frac {b x^{3} e^{i \pi }}{a}} \right )}}{3 e^{\frac {3}{2}} \Gamma \left (\frac {23}{6}\right )} \]

input
integrate((b*x**3+a)**(5/2)*(B*x**3+A)/(e*x)**(3/2),x)
 
output
A*a**(5/2)*gamma(-1/6)*hyper((-1/2, -1/6), (5/6,), b*x**3*exp_polar(I*pi)/ 
a)/(3*e**(3/2)*sqrt(x)*gamma(5/6)) + 2*A*a**(3/2)*b*x**(5/2)*gamma(5/6)*hy 
per((-1/2, 5/6), (11/6,), b*x**3*exp_polar(I*pi)/a)/(3*e**(3/2)*gamma(11/6 
)) + A*sqrt(a)*b**2*x**(11/2)*gamma(11/6)*hyper((-1/2, 11/6), (17/6,), b*x 
**3*exp_polar(I*pi)/a)/(3*e**(3/2)*gamma(17/6)) + B*a**(5/2)*x**(5/2)*gamm 
a(5/6)*hyper((-1/2, 5/6), (11/6,), b*x**3*exp_polar(I*pi)/a)/(3*e**(3/2)*g 
amma(11/6)) + 2*B*a**(3/2)*b*x**(11/2)*gamma(11/6)*hyper((-1/2, 11/6), (17 
/6,), b*x**3*exp_polar(I*pi)/a)/(3*e**(3/2)*gamma(17/6)) + B*sqrt(a)*b**2* 
x**(17/2)*gamma(17/6)*hyper((-1/2, 17/6), (23/6,), b*x**3*exp_polar(I*pi)/ 
a)/(3*e**(3/2)*gamma(23/6))
 
3.6.40.7 Maxima [F]

\[ \int \frac {\left (a+b x^3\right )^{5/2} \left (A+B x^3\right )}{(e x)^{3/2}} \, dx=\int { \frac {{\left (B x^{3} + A\right )} {\left (b x^{3} + a\right )}^{\frac {5}{2}}}{\left (e x\right )^{\frac {3}{2}}} \,d x } \]

input
integrate((b*x^3+a)^(5/2)*(B*x^3+A)/(e*x)^(3/2),x, algorithm="maxima")
 
output
integrate((B*x^3 + A)*(b*x^3 + a)^(5/2)/(e*x)^(3/2), x)
 
3.6.40.8 Giac [F]

\[ \int \frac {\left (a+b x^3\right )^{5/2} \left (A+B x^3\right )}{(e x)^{3/2}} \, dx=\int { \frac {{\left (B x^{3} + A\right )} {\left (b x^{3} + a\right )}^{\frac {5}{2}}}{\left (e x\right )^{\frac {3}{2}}} \,d x } \]

input
integrate((b*x^3+a)^(5/2)*(B*x^3+A)/(e*x)^(3/2),x, algorithm="giac")
 
output
integrate((B*x^3 + A)*(b*x^3 + a)^(5/2)/(e*x)^(3/2), x)
 
3.6.40.9 Mupad [F(-1)]

Timed out. \[ \int \frac {\left (a+b x^3\right )^{5/2} \left (A+B x^3\right )}{(e x)^{3/2}} \, dx=\int \frac {\left (B\,x^3+A\right )\,{\left (b\,x^3+a\right )}^{5/2}}{{\left (e\,x\right )}^{3/2}} \,d x \]

input
int(((A + B*x^3)*(a + b*x^3)^(5/2))/(e*x)^(3/2),x)
 
output
int(((A + B*x^3)*(a + b*x^3)^(5/2))/(e*x)^(3/2), x)